二分贪心-B

Description

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogday cat atcay pig igpay froot ootfray loops oopslay atcay ittenkay oopslay

Sample Output

cat eh loops

Hint

Huge input and output,scanf and printf are recommended.

这道题的意思就是相当于一个字典表将异邦语翻译成英文，先会输入翻译表，所以我觉得用map会很方便。键值为异邦语，元素为相应的英文。

下面是我的ac代码：

#include <iostream> #include <string> #include <stdio.h> #include <map> using namespace std; const int N = 100; int main() { char str[N], aid[N], ans[N]; map<string, string> vec; while (gets(str) && str[0] != '\0') { sscanf(str, "%s%s", ans, aid); vec[aid] = ans; } while(gets(aid)) { if (vec.find(aid) == vec.end()) cout << "eh" << endl; else cout << vec[aid] << endl; } return 0; } <iostream> #include <string> #include <stdio.h> #include <map> using namespace std; const int N = 100; int main() { char str[N], aid[N], ans[N]; map<string, string> vec; while (gets(str) && str[0] != '\0') { sscanf(str, "%s%s", ans, aid); vec[aid] = ans; } while(gets(aid)) { if (vec.find(aid) == vec.end()) cout << "eh" << endl; else cout << vec[aid] << endl; } return 0; }