Given a group of two strings, you need to find the longest uncommon subsequence of this group of two strings. The longest uncommon subsequence is defined as the longest subsequence of one of these strings and this subsequence should not be any subsequence of the other strings.
A subsequence is a sequence that can be derived from one sequence by deleting some characters without changing the order of the remaining elements. Trivially, any string is a subsequence of itself and an empty string is a subsequence of any string.
The input will be two strings, and the output needs to be the length of the longest uncommon subsequence. If the longest uncommon subsequence doesn't exist, return -1.
Example 1:
Input: "aba", "cdc" Output: 3 Explanation: The longest uncommon subsequence is "aba" (or "cdc"), because "aba" is a subsequence of "aba", but not a subsequence of any other strings in the group of two strings.
Note:
Both strings' lengths will not exceed 100.Only letters from a ~ z will appear in input strings. 额。。。题意是寻找两个字符串中最长的唯一的子字符串的长度，在一个字符串有，另一个字符串没有。字符串本身也算是他的子字符串。那么……如果两个字符串相同，就没有特别的子字符串，返回-1；如果两个字符串不同，较长的字符串整体就是一个唯一的子字符串，返货较长的字符串的长度。看了很长时间的题，感觉像是脑筋急转弯。代码如下： public class Solution { public int findLUSlength(String a, String b) { return a.equals(b)? -1: Math.max(a.length(), b.length()); } }