Given an absolute path for a file (Unix-style), simplify it.
For example,path = "/home/", => "/home"path = "/a/./b/../../c/", => "/c"path = "/a/../../b/../c//.//", => "/c"path = "/a//bc/d//././/..", => "/a/b/c"
In a UNIX-style file system, a period ('.') refers to the current directory, so it can be ignored in a simplified path. Additionally, a double period ("..") moves up a directory, so it cancels out whatever the last directory was. For more information, look here: https://en.wikipedia.org/wiki/Path_(computing)#Unix_style
Corner Cases:
Did you consider the case where path = "/../"? In this case, you should return "/".Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/". In this case, you should ignore redundant slashes and return "/home/foo".居然WA了一上午 还是看标称的
居然还有/.../这种无耻的路径
学会了一个新函数
istringstream ss(path); while(getline(ss, val, '/')){ class Solution { public: string simplifyPath(string path) { vector<string>ans; string val; istringstream ss(path); while(getline(ss, val, '/')){ if(val==".."){ if(!ans.empty()) ans.erase(ans.end()); } else if(val=="."){ continue; } else{ if(val!="") ans.push_back(val); } } string re=""; for(int i=0;i<ans.size();i++) { re+='/'; re+=ans[i]; } if(re=="") re+='/'; return re; } };
